Mount Base
What is the boiling temperature of water at Base Camp of Mount Everest (altitude 5300m)?
T = boiling point in Kelvins
h = altitude in meters
T = (1.518 * 10^7) / (40700 + 0.828582 * h)
T = (1.518 * 10^7) / (40700 + 0.828582 * 5300
T = 336.758255 K
T = 63.758255° C = 63.8° C (64° C observing significant digits)
T = 129.213208° F = 129.2° F (130° F observing sigfigs)
That won't be exact, because atmospheric pressure won't be exact, but that's a good approximation.
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